引用第656楼iongwaichun于2008-12-02 21:45发表的 :) {- F$ s; O8 y2 p0 q* l$ T
P8:) a6 M9 v1 s: `* c# G$ P) `1 ?
1114523221
; m9 a% i2 Z% F0 P1 h6 l5 K* o重做一次後,Here is my solution
) d# q. J2 V7 o* ~8 H7 R8 V; |0 J" O, m
+ n8 w$ n. s( c$ L
P8:9 q& [$ m* U: s* _ {
Here is my deduction:, @( J/ y1 C1 ` o7 D! t. ^- ^
From the left 3 digit, we can deduct the following:
% Y. r) [6 S1 K1 F; L4 z6 R# R5 J1122 o* l" g) S$ D' z7 g! h. o8 U
111
9 O# x6 {3 g0 a; X! z5 O( L5 ^1125 b' P! M$ A0 ] Z4 r: p! H
111
# b4 h. k$ n! _; C# n0 E113
3 G) q, b8 e& y: X4 l: {So, the final line = 111, l: h8 u' o3 g/ K& e6 t( L3 d
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, k3 H$ S* O9 h
From the right 3 digit, we can deduct the following(S):: r9 a& |8 u& ~
121' r6 m$ Z' T; m0 j5 b
221
, c- m/ p6 w, p3 h0 }1 r231
: B$ E; m/ }" S3 p221
) n4 }# b0 n' `. n# u331, u- M/ O7 t& H1 D) L+ n& |
4 G4 x5 ^ b9 N' O1 zSo, the final Line = 2216 N% T) h! v, v- t6 r/ ]: E7 I" p
% C. _ h" j& j, k& L$ g4 K3 vIn the uppesmost line, the middle letters had been use twice, they are 1 and 2
+ C4 _4 M: K: v* a2 W$ J3 x7 xFrom the remaining numbers, there are 32 on the second last line provided,: _6 m+ H# e# O# A m8 k9 u
and 21 on the last line
1 a& x, t( \6 g+ T* I2 L
, [4 J3 A% g6 X$ x" hWe now had the sequence:8 P6 O- t5 W8 f1 A& P
12
+ l& w- x2 {7 F3 U7 v32; v3 X7 B: t, b
21( ]# r5 W. j3 k' b# W) F9 m; v
0 ]; R/ L$ I* c! y/ ~( i+ w
So, the last line's middle numbers is 23 (exchange the two numbers)2 q n, o3 l1 I
- Y' u; s, c9 |4 H4 x' ~Now we have the following numbers:
$ o! }( _1 V; E/ w1 c( J) z7 N111x23y2218 I% j# x7 ~: H1 F
Culculate the total of every line, then we can conclude the following8 F' M% \1 a: V7 e0 f
Difference between line 1 and line 2=3
6 f' i" z2 s" G: C; EDifference between line 2 and line 3=2
8 }' U0 \9 x5 F) Z6 P$ GDifference between line 3 and line 4=3
4 d! Y; y* c" u' j9 A; `* E4 gDifference between line 4 and line 5=29 U% y) T5 Y3 n) D
So, Difference between line 5 and line 6=3
2 l6 f! k5 v7 c0 A
7 c8 T; H- A, I' H! Q S3 m8 O5 wBut now, the total of our deduction=13
% L* B" ]0 C9 m- H9 q! bLine 5's total=15" L6 c: O6 G3 E
which means X+Y=(15+3)-13: Z! ^& E7 }; D% r3 H0 j, E4 O: a" y
=18-13
, @- U' ]5 B( j! q2 Y( U% T =5* _8 A' E6 r% E9 L" E+ f
So, If x=2, y=3: E c6 f) c0 C" _- j9 O: `% R
x=3, y=29 P6 Q8 I. |! h( G
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+ D6 j/ Q/ I# c8 `4 z
Ans=1112233221 - P& \7 _; C: Z8 _( k/ \
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Ans=1113232221 |