引用第656楼iongwaichun于2008-12-02 21:45发表的 :
1 Z& B) w; J% _+ r; p5 _6 PP8:, c+ y( ]% L; {, [7 \
1114523221
重做一次後,Here is my solution
/ r2 }) D% B0 f" V G2 C) |$ H; e0 c
! h$ L) \) y6 F8 e& L- o
P8:
" k+ O7 E( T# |( z# rHere is my deduction:
; |+ S. U7 h" |0 Y/ j P4 q# o) uFrom the left 3 digit, we can deduct the following:
! o ?9 [* m5 i" c4 R* f112
+ a8 l: o# z/ ?, g7 d1115 r" I/ C& `+ u, K# G5 L: l
112. z0 O4 n3 B! p% @8 O8 J
111
) K) S; T+ }0 h2 R$ e- x0 w1131 R8 F- @% b6 A9 T1 m6 ^( ^
So, the final line = 111
9 ]! w$ I2 o9 c8 M: Q4 h7 K$ k. Z! L$ Y
3 j6 [, [9 O. T# G! X) [) ^* ~
From the right 3 digit, we can deduct the following(S):
h. I* A6 a: [1217 {: x1 V0 ^/ }* H4 R
221' l& X6 J+ H% b5 i7 N5 m
231
. D* @) u a6 R" F$ z221
* w" Y0 L9 q1 g' ?4 X. ]331! R; E6 Z% V# b2 O- f
{% u3 U! Q- c* CSo, the final Line = 221
0 |) t9 x7 R% w7 A* X4 e' d
! }' G, N) z: _- J- J3 m. Y/ GIn the uppesmost line, the middle letters had been use twice, they are 1 and 2- Q9 w, b. T: g# j5 E
From the remaining numbers, there are 32 on the second last line provided,
) y6 M: j5 [ J! J: [and 21 on the last line
; ~0 m; c6 \# g7 m% n) z: x# Q( K \
; _% C; T& e% E# N" ?We now had the sequence:
4 \9 G+ H7 p$ ~# Q' s) L12) u; t7 @" U' M: \- q0 F
32
a/ f2 }+ w" L. z2 s/ }* }% O4 G21, D- o+ K! ^& l) S7 q1 a
+ N- v, Q( |0 j1 Q' ?1 q
So, the last line's middle numbers is 23 (exchange the two numbers)+ x/ x' U' l2 a7 S$ m0 k
A: T/ X/ n& G; r. aNow we have the following numbers:
5 O4 u6 F; [3 W% q! ]111x23y221, j! f9 P/ M& j/ ]# q+ ^
Culculate the total of every line, then we can conclude the following( a+ E( N0 t5 U& w
Difference between line 1 and line 2=3' @- v* p5 e$ e5 H8 R2 A
Difference between line 2 and line 3=2
9 `- ^7 g! K8 @* HDifference between line 3 and line 4=3
% N5 ]4 I: f5 H, ^- J& zDifference between line 4 and line 5=2
6 S( [& z4 _% R1 Z9 Y# s3 L6 w) ESo, Difference between line 5 and line 6=3
- R( J+ F k4 S- [& e. B7 M2 n h1 Q3 c7 P+ w' K0 E' }
But now, the total of our deduction=13
: _' C$ ~+ e; M( d K+ ]4 eLine 5's total=15
" H/ [, \6 Q9 B1 L- e* }0 f5 `which means X+Y=(15+3)-13
' B- {# k# s+ Q' E =18-13+ D' `/ q, K* ^, Z! Z: ~, t
=56 ?4 M7 z* q$ J b, r: `# L
So, If x=2, y=3; b0 \5 Q# R X2 r. i0 Q' D
x=3, y=2
' C( t; ] b: A, d( |9 \4 ^, v5 `& V A- d
- L P. E# j; a" s6 e) T) OAns=1112233221 # x" d: X4 |. L" ^
or
& N* Z, @/ W9 MAns=1113232221 |
楼主
发表于 2008-12-2 21:40
